Mathematics
Draw an ∠ABC = 60°, having AB = 4.6 cm and BC = 5 cm. Find a point P equidistant from AB and BC; and also equidistant from A and B.
Answer
Steps of construction :
Draw a line segment BC = 5 cm.
At B, draw a ray BX making an angle of 60° and cut off BA = 4.6 cm.
Draw BY, the angle bisector of ∠ABC.
Draw MN, the perpendicular bisector of AB.
Let MN and BY meet at point P.
Hence, P is the point which is equidistant from AB and BC, as well as from A and B.
Related Questions
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