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Mathematics

Diameter of the base of a cone is 10.5 cm and its slant height is 10 cm. Find its curved surface area.

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Answer

Given,

Diameter of cone (d) = 10.5 cm

Slant height of cone (l) = 10 cm

By formula,

Radius of cone (r) = Diameter2=10.52\dfrac{\text{Diameter}}{2} = \dfrac{10.5}{2} = 5.25 cm

Diameter of the base of a cone is 10.5 cm and its slant height is 10 cm. Find its curved surface area. NCERT Class 9 Mathematics CBSE Solutions.

By formula,

Curved surface area of cone (C.S.A.) = πrl

Substituting values we get :

C.S.A.=227×5.25×10=11557=165 cm2\text{C.S.A.} = \dfrac{22}{7} × 5.25 × 10 \\[1em] = \dfrac{1155}{7} \\[1em] = 165 \text{ cm}^2

Hence, curved surface area of the cone = 165 cm2.

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