Construct a parallelogram ABCD with diagonals 6.3 cm and 5.6 cm. And, acute angle between the diagonals is 45°.

Let parallelogram ABCD has diagonal AC = 6.3 cm, diagonal BD = 4.8 cm and the acute angle between the diagonals = 45°. Steps of construction : 1. Draw a line AC = 6.3 cm and locate its mid point O. 2. Draw line BOD such that ∠DOC = 45° and OB = OD = BD = x 5.6 cm = 2.8 cm 3. Join AB, BC, CD and DA. Hence, ABCD is the required parallelogram.