Construct a parallelogram ABCD with diagonals 6.3 cm and 5.6 cm. And, acute angle between the diagonals is 45°.

Let parallelogram ABCD has diagonal AC = 6.3 cm, diagonal BD = 4.8 cm and the acute angle between the diagonals = 45°.

Steps of construction :

1. Draw a line AC = 6.3 cm and locate its mid point O.

2. Draw line BOD such that ∠DOC = 45° and OB = OD = $\dfrac{1}{2}$ BD = $\dfrac{1}{2}$ x 5.6 cm = 2.8 cm

3. Join AB, BC, CD and DA.

Hence, ABCD is the required parallelogram.