Mathematics

Construct a triangle BCP given BC = 5 cm, BP = 4 cm and ∠PBC = 45°.

(i) Complete the rectangle ABCD such that :

(a) P is equidistant from AB and BC.

(b) P is equidistant from C and D.

(ii) Measure and record the length of AB.

Locus

20 Likes

Answer

Construct a triangle BCP given BC = 5 cm, BP = 4 cm and ∠PBC = 45°.

(i) Steps of construction :

Complete the rectangle ABCD such that P is equidistant from AB and BC. P is equidistant from C and D. Measure and record the length of AB. Loci, Concise Mathematics Solutions ICSE Class 10.
  1. Draw a line segment BC = 5 cm.

  2. With B as center draw an arc BX, at an angle of 45°.

  3. From BX cut off BP = 4 cm.

  4. Join PC. Hence, BPC is the required triangle.

  5. Draw perpendicular on B and C.

  6. With P as center and radius PC, cut an arc on the perpendicular on C at D.

  7. From D, draw a line parallel to BC which intersects the perpendicular on B at A.

Hence, ABCD is the required rectangle.

(ii) On measuring we get,

AB = 5.7 cm.

Answered By

13 Likes


Related Questions