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Chemistry

Calculate the volume occupied by 320 g of sulphur dioxide at S.T.P.

[S = 32; O = 16]

Mole Concept

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Answer

Molar mass of sulphur dioxide (SO2) = S + 2O = 32 + (2 x 16) = 32 + 32 = 64 g

64 g of sulphur dioxide has volume = 22.4 litre

∴ 320 g of sulphur dioxide will have volume = 22.4×32064\dfrac{22.4\times 320}{64}

= 112 litres

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