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Chemistry

Calculate the mass of nitrogen supplied to soil by 5 kg of urea [CO(NH2)2]

[O = 16; N = 14; C = 12 ; H = 1 ]

Mole Concept

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Answer

Molar mass of urea [CO(NH2)2] = 12 + 16 + 2(14 + (2 x 1))

= 28 + 2(16)

= 28 + 32

= 60 g

Molar mass of nitrogen = 2 x 14 = 28 g

60 g urea has mass of nitrogen = 28 g

∴ 5000 g urea will have mass

= 28×500060\dfrac{28 \times 5000 }{60}

= 2333 g = 2.33 kg

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