Chemistry
Calculate the no. of moles and the no. of molecules present in 1.4 g of ethylene gas (C2H4). What is the vol. occupied by the same amount of C2H4. State the vapour density of C2H4.
(Avog. No. = 6 × 1023 ; C = 12, H = 1]
Stoichiometry
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Answer
Gram molecular mass of C2H4
= 2(12) + 4(1)
= 24 + 4 = 28 g
As,
28 g of C2H4 = 1 mole
∴ 1.4 g of C2H4 = x 1.4 = 0.05 moles
1 mole = 6 × 1023 molecules
∴ 0.05 moles = 6 × 1023 x 0.05 = 3 x 1022 molecules
Hence, no. of moles is 0.05 and no. of molecules is 3 x 1022.
Vol. occupied by 1 mole = 22.4 lit
∴ Vol. occupied by 0.05 moles = 22.4 x 0.05 = 1.12 lit.
Hence, vol. occupied is 1.12 lit and vapour density is 14
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