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Chemistry

Calculate the amount of each reactant required to produce 750 ml of carbon dioxide as per the equation.

2CO + O2 ⟶ 2CO2

State the law associated in the question.

Stoichiometry

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Answer

[By Lussac's law]

2CO+O2⟶2CO22 vol.:1 vol.⟶2 vol.\begin{matrix} 2\text{CO}& + & \text{O}2 &\longrightarrow & 2\text{CO}2 \ 2 \text{ vol.} & : & 1 \text{ vol.} & \longrightarrow & 2\text{ vol.} \end{matrix}

To calculate the amount of CO required :

CO2:CO2 vol.:2 vol.750 ml:x\begin{matrix}\text{CO}_2 & : & \text{CO} & \ 2 \text{ vol.} & : & 2 \text{ vol.} \ 750 \text{ ml} & : & \text{x} \end{matrix}

∴x=22×750=750 ml\therefore x = \dfrac{2}{2} \times 750 = 750 \text{ ml}

To calculate the amount of O2 required :

CO2:O2 2 vol.:1 vol.750 cm.3:x\begin{matrix}\text{CO}2 & : & \text{O}2 & \ \text{ 2 vol.} & : & 1 \text{ vol.} \ 750 \text{ cm.}^3 & : & \text{x} \end{matrix}

∴x=12×750=375 ml\therefore x = \dfrac{1}{2} \times 750 = 375 \text{ ml}

Hence, CO required is 750 ml and O2 required = 375 ml

Gay Lussac's law is associated in the question.

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