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Calculate AB. Heights and Distances, Concise Mathematics Solutions ICSE Class 10.

Heights & Distances

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Answer

In △ACD,

Calculate AB. Heights and Distances, Concise Mathematics Solutions ICSE Class 10.

cos 30°=BaseHypotenuse32=ADCDAD=32×CDAD=32×6AD=33AD=5.196 m.\text{cos 30°} = \dfrac{\text{Base}}{\text{Hypotenuse}} \\[1em] \Rightarrow \dfrac{\sqrt{3}}{2} = \dfrac{AD}{CD} \\[1em] \Rightarrow AD = \dfrac{\sqrt{3}}{2} \times CD \\[1em] \Rightarrow AD = \dfrac{\sqrt{3}}{2} \times 6 \\[1em] \Rightarrow AD = 3\sqrt{3} \\[1em] \Rightarrow AD = 5.196 \text{ m}.

In △BDE,

sin 47°=PerpendicularHypotenuse0.73=BDDEBD=0.73×DEBD=0.73×5=3.65 m.\text{sin 47°} = \dfrac{\text{Perpendicular}}{\text{Hypotenuse}} \\[1em] \Rightarrow 0.73 = \dfrac{BD}{DE} \\[1em] \Rightarrow BD = 0.73 \times DE \\[1em] \Rightarrow BD = 0.73 \times 5 = 3.65 \text{ m}.

From figure,

AB = AD + BD = 5.196 + 3.65 = 8.846 = 8.85 meters.

Hence, AB = 8.85 meters.

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