By, means of an example, show that sin(A + B) ≠ sin A + sin B.

Let A = 30° and B = 60°. Substituting values in sin(A + B) we get : ⇒ sin(A + B) = sin(30° + 60°) = sin 90° = 1. Substituting values in sin A + sin B we get : ⇒ sin A + sin B = sin 30° + sin 60° = = . As, LHS ≠ RHS Hence, proved that sin(A + B) ≠ sin A + sin B.