Mathematics
By, means of an example, show that sin(A + B) ≠ sin A + sin B.
Trigonometrical Ratios
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Answer
Let A = 30° and B = 60°.
Substituting values in sin(A + B) we get :
⇒ sin(A + B) = sin(30° + 60°) = sin 90° = 1.
Substituting values in sin A + sin B we get :
⇒ sin A + sin B = sin 30° + sin 60°
=
= .
As, LHS ≠ RHS
Hence, proved that sin(A + B) ≠ sin A + sin B.
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