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An electric iron of resistance 20 Ω takes a current of 5 A. Calculate the heat developed in 30 s.

Current Electricity

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Answer

Given,

R = 20 Ω
I = 5 A
t = 30 s

According to Joule's law of heating,

H = I2Rt

Substituting the values, we get,

H = 5 x 5 x 20 x 30 = 15000 J

Therefore, amount of heat developed = 15000 J.

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