Physics

An electric bulb draws 1.2 A current at 6.0 V. Find the resistance of filament of bulb while glowing.

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Given,

Current (I) = 1.2 A

Potential difference (V) = 6.0 V

Resistance (R) = ?

From Ohm's law

V = IR

Substituting the values in the formula above, we get,

$6 = 1.2 \times R \\[0.5em] \Rightarrow R = \dfrac{6}{1.2} \\[0.5em] \Rightarrow R = 5 \varOmega$

Hence, resistance of filament of bulb = 5 Ω

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