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A car bulb connected to a 12 volt battery draws 2 A current when glowing. What is the resistance of the filament of the bulb? Will the resistance be more, same or less when the bulb is not glowing.

Current Electricity

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Answer

Given,

Potential difference (V) = 12 V

Current (I) = 2 A

Resistance = ?

From Ohm's law

V = IR

Substituting the values in the formula above, we get,

12=2×R⇒R=122⇒R=6Ω12 = 2 \times R \\[0.5em] \Rightarrow R = \dfrac{12}{2} \\[0.5em] \Rightarrow R = 6 \varOmega

Hence, the resistance of the filament of the bulb = 6 Ω

The resistance will be less when the bulb is not glowing.

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