Mathematics
ABCD is a trapezium with AD parallel to BC. Side BC is produced to point E and angle DCE = 95°. Angle B is equal to :
85°
105°
95°
175°

Circles
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Answer
Given,
AD || BC
Since,
Side BC is produced to point E.
We can say that,
AD || BE
From figure,
∠ADC = ∠DCE = 95° (Alternate angles are equal)
We know that,
The opposite angles of a cyclic quadrilateral are supplementary.
∴ ∠ADC + ∠CBA = 180°
⇒ ∠CBA = 180° - ∠ADC = 180° - 95° = 85°.
Hence, Option 1 is the correct option.
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