Mathematics
ABCD is a rhombus such that ∠ACB = 40°. Then ∠ADB is
40°
45°
50°
60°
Rectilinear Figures
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Answer
From figure,
⇒ ∠DAO = ∠OCB = 40° (Alternate angles are equal.)
In △ADO,
⇒ ∠DAO + ∠AOD + ∠ODA = 180°
⇒ 40° + 90° + ∠ODA = 180°
⇒ ∠ODA = 180° - 130° = 50°.
From figure,
∠ADB = ∠ODA = 50°.
Hence, Option 3 is the correct option.
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