Mathematics
ABC is a triangle. Point P moves with vertex B as center and radius 2.8 cm. The locus of point P is :
bisector of angle ABC.
a line parallel to BC and at a distance of 2.8 cm from it.
circle with center at point B and radius = 2.8 cm.
perpendicular bisector of BC.
Answer
We know that,
Locus of a point, in a plane and at a fixed distance from a given fixed point, is the circumference of the circle with the given fixed point as center and given fixed distance as radius.
∴ The locus of point P is a circle with center at point B and radius = 2.8 cm.
Hence, Option 3 is the correct option.
Related Questions
Locus of the centers of the circles passing through two fixed points A and B is :
a line parallel to line segment AB.
the bisector of the line segment AB.
perpendicular to line segment AB.
perpendicular bisector of line segment AB.
A point is equidistant from the sides of an obtuse angle triangle. The point is called :
circumcenter of the triangle.
incenter of the triangle.
centroid of the triangle.
orthocenter of the triangle.
Draw an ∠ABC = 60°, having AB = 4.6 cm and BC = 5 cm. Find a point P equidistant from AB and BC; and also equidistant from A and B.
On a graph paper, draw the lines x = 3 and y = -5. Now, on the same graph paper, draw the locus of the point which is equidistant from the given lines.