Mathematics
AB is a diameter of a circle with centre O. Chord CD is equal to radius OC. AC and BD produced intersect at P. Prove that : ∠APB = 60°.
![AB is a diameter of a circle with centre O. Chord CD is equal to radius OC. AC and BD produced intersect at P. Prove that : ∠APB = 60°. Chapterwise Revision, Concise Mathematics Solutions ICSE Class 10.](https://cdn1.knowledgeboat.com/img/cm10/q81b-chapterwise-revision-concise-maths-solutions-icse-class-10-782x924.png)
Related Questions
In the given figure, AB and XY are diameters of a circle with center O. If ∠APX = 30°, find :
(i) ∠AOX
(ii) ∠APY
(iii) ∠BPY
(iv) ∠OAX
In the adjoining figure; AB = AD, BD = CD and ∠DBC = 2∠ABD. Prove that : ABCD is a cyclic quadrilateral.
In the given figure, AC = AB and ∠ABC = 72°. OA and OB are two tangents. Determine :
(i) ∠AOB
(ii) angle subtended by the chord AB at the center.
In the given figure, PQ, PR and ST are tangents to the same circle. If ∠P = 40° and ∠QRT = 75°, find a, b and c.