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A vertical tower is 20 m high. A man standing at some distance from the tower knows that the cosine of the angle of elevation of the top of the tower is 0.53. How far is he standing from the foot of the tower ?

Heights & Distances

ICSE

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Answer

Let θ be the angle of elevation,

A vertical tower is 20 m high. A man standing at some distance from the tower knows that the cosine of the angle of elevation of the top of the tower is 0.53. How far is he standing from the foot of the tower? Heights and Distances, ML Aggarwal Understanding Mathematics Solutions ICSE Class 10.

Given, cos θ = 0.53

∴ cos θ = cos 58°

⇒ θ = 58°

Let MP be the vertical tower and the man be standing at point O.

Considering △POM,

∠PMO = 90°, ∠POM = 58° and MP = 20 m.

From △POM, we get

tan 58°=MPOM1.6003=20OMOM=201.6003OM=12.4912.5\Rightarrow \text{tan 58°} = \dfrac{MP}{OM} \\[1em] \Rightarrow 1.6003 = \dfrac{20}{OM} \\[1em] \Rightarrow OM = \dfrac{20}{1.6003} \\[1em] \Rightarrow OM = 12.49 \approx 12.5

Hence, the man is at a distance of 12.5 metres from the foot of tower.

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