Physics

A simple pendulum completes 40 oscillations in one minute.
Find its —
(a) frequency,
(b) time period.

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(a) Given,

40 oscillations in one minute, so

$\text {frequency per second} = \dfrac{40}{60} \\[0.5em] = \dfrac{2}{3} \\[0.5em] = \text {0.67} s^{-1} \\[0.5em]$

Hence, frequency of oscillation = 0.67 s^-1.

(b) As we know that,

$T = \dfrac{1}{f}$

So, substituting the value of f = 0.67 s^-1, in equation above we get,

$T = \dfrac{1}{0.67} \\[0.5em] \Rightarrow T = 1.49253s \approx 1.5s \\[0.5em]$

Hence, time period of the simple pendulum is 1.5 s.

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