Chemistry
A sample of ammonium nitrate when heated yields 8.96 litres of steam (measured at STP)
NH4NO3 ⟶ N2O + 2H2O
(i) What volume of di nitrogen oxide is produced at the same time as 8.96 litres of steam.
(ii) What mass of ammonium nitrate should be heated to produce 8.96 litres of steam [Relative molecular mass of NH4NO3 is 80]
(iii) Determine the percentage of oxygen in ammonium nitrate [O = 16]
Mole Concept
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Answer
(i) Given,
1 vol. of di nitrogen produced at the same time as 8.96 litres of steam (2 vol)
Hence, Vol of di nitrogen = = 4.48 lit.
Hence, volume of di nitrogen oxide produced = 4.48 lit.
(ii) 2 vol = (2 x 22.4) lit steam is produced from 80 g NH4NO3
∴ 8.96 lit of steam will be produced by x 8.96 = 16 g
Hence, 16 g of ammonium nitrate is required to be heated.
(iii) % of oxygen in ammonium nitrate = x 100 = 60 %
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