A road 3.5 m wide surrounds a circular park whose circumference is 88 m. Find the cost of paving the road at the rate of ₹60 per square metre.

Given, Circumference of circular park = 88 m Let radius of circular park be r meters. 2πr = 88 From figure, Radius of outer circle (R) = Radius of circular park + Width of road = 14 + 3.5 = 17.5 m Area of road = Area of outer circle - Area of circular park = πR 2 - πr 2 = π(17.5) 2 - π(14) 2 = π[306.25 - 196] = 110.25π = = 346.5 m 2 . Cost of paving the road = Area of road × Rate = 346.5 × 60 = ₹ 20790. Hence, cost of paving road = ₹ 20790.

The adjoining sketch shows a running track 3.5 m wide all around which consists of two straight paths and two semicircular rings. Find the area of the track.

View Answer Bookmark Now

From a sheet of paper of dimensions 2 m × 1.5 m, how many circles of radius 5 cm can be cut? Also find the area of the paper wasted. (Take π = 3.14)

View Answer Bookmark Now

If the diameter of a semi-circular protractor is 14 cm, then find its perimeter.

View Answer Bookmark Now

In the adjoining figure, O is the center of a circular arc and AOB is a line segment. Find the perimeter and the area of the shaded region correct to one decimal place. (Take π = 3.142)

View Answer Bookmark Now

Mathematics

A road 3.5 m wide surrounds a circular park whose circumference is 88 m. Find the cost of paving the road at the rate of ₹60 per square metre.

Mensuration

Related Questions

The adjoining sketch shows a running track 3.5 m wide all around which consists of two straight paths and two semicircular rings. Find the area of the track.

From a sheet of paper of dimensions 2 m × 1.5 m, how many circles of radius 5 cm can be cut? Also find the area of the paper wasted. (Take π = 3.14)

If the diameter of a semi-circular protractor is 14 cm, then find its perimeter.

In the adjoining figure, O is the center of a circular arc and AOB is a line segment. Find the perimeter and the area of the shaded region correct to one decimal place. (Take π = 3.142)