Physics

A nucleus ₈₄X²⁰² of an element emits an alpha particle followed by a beta particle. The final nucleus is _aY^b. Find a and b.

Radioactivity

ICSE 2020

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Answer

The emission of alpha and beta particle is represented below:

$_{84}^{202}\text{X} \longrightarrow \space _{82}^{198}\text{Z} + \space _{2}^{4}\text{He} \text{ (α particle emission)} \\[2em] _{82}^{198}\text{Z} \longrightarrow \space _{83}^{198}\text{Y} + \space _{-1}^{\space \space \space 0}e \text{ (β particle emission)}$

∴ a = 83 and b = 198

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Physics

A nucleus ₈₄X²⁰² of an element emits an alpha particle followed by a beta particle. The final nucleus is _aY^b. Find a and b.

Radioactivity

ICSE 2020

Answer

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Physics

A nucleus 84X202 of an element emits an alpha particle followed by a beta particle. The final nucleus is aYb. Find a and b.

Radioactivity

ICSE 2020

Answer

Related Questions

Two metallic blocks P and Q having masses in ratio 2 : 1 are supplied with the same amount of heat. If their temperatures rise by same degree, compare their specific heat capacities.

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A nucleus ₈₄X²⁰² of an element emits an alpha particle followed by a beta particle. The final nucleus is _aY^b. Find a and b.

The diagram alongside shows a loop of wire carrying current I:
(i) What is the magnetic polarity of the loop that faces us?
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