Two parallelograms are on equal bases and between the same parallels. The ratio of their areas is

1. 1 : 2

2. 1 : 1

3. 2 : 1

4. 3 : 1

If a triangle and a parallelogram are on the same base and between same parallels, then the ratio of area of the triangle to the area of parallelogram is

1. 1 : 3

2. 1 : 2

3. 3 : 1

4. 1 : 4

In the adjoining figure, area of parallelogram ABCD is

1. AB × BM

2. BC × BN

3. DC × DL

4. AD × DL

The mid-points of the sides of a triangle along with any of the vertices as the fourth point make a parallelogram of area equal to

1. $\dfrac{1}{2}$ area of △ABC

2. $\dfrac{1}{3}$ area of △ABC

3. $\dfrac{1}{4}$ area of △ABC

4. area of △ABC