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A line intersects x-axis at point (-2, 0) and cuts off an intercept of 3 units from the positive side of y-axis. Find the equation of the line.

Straight Line Eq

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Answer

Let line intersect x-axis at point A.

So, A = (-2, 0)

Let line cuts off an intercept of 3 units from positive side of y-axis at point B.

So, co-ordinates of B are (0, 3).

By formula,

Slope = y2y1x2x1\dfrac{y2 - y1}{x2 - x1}

Slope of AB = 300(2)=32\dfrac{3 - 0}{0 - (-2)} = \dfrac{3}{2}.

By point-slope form,

Equation of AB is :

⇒ y - y1 = m(x - x1)

⇒ y - 0 = 32\dfrac{3}{2}[x - (-2)]

⇒ 2y = 3(x + 2)

⇒ 2y = 3x + 6

⇒ 3x - 2y + 6 = 0

⇒ 2y = 3x + 6.

Hence, equation of AB is 2y = 3x + 6.

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