Physics
A light ray of yellow colour is incident on an equilateral glass prism at an angle of incidence equal to 48° and suffers minimum deviation by an angle of 36°.
(i) What will be the angle of emergence?
(ii) If the angle of incidence is changed to (a) 30°, (b) 60°, state in each case whether the angle of deviation will be equal to less than or more than 36°?
Answer
(i) As we know that in an equilateral glass prism the ray suffers minimum deviation.
So, angle of incidence i1 is equal to angle of emergence i2
Given, angle of incidence i1 = 48°
Applying the rule given above, we get,
i1 = i2
⇒ i2 = 48°
Hence, angle of emergence i2 = 48°
(ii) (a) As the minimum angle of deviation is 36° for yellow light, at an incident angle of 48° so for any angle of incidence other than 48° the angle of deviation will be more than 36°.
Hence, when the angle of incidence is changed to 30°, the angle of deviation will be more than 36°.
(b) As the minimum angle of deviation is 36° for yellow light, at an incident angle of 48° so for any angle of incidence other than 48° the angle of deviation will be more than 36°.
Hence, when the angle of incidence is changed to 60°, the angle of deviation will be more than 36°.
Related Questions
How does the deviation produced by a prism depend on
(i) the refractive index of its material, and
(ii) the wavelength of incident light
How does the angle of deviation depend on refracting angle of the prism?
Define the term angle of deviation.
A ray of light incident at an angle of incidence i1 passes through an equilateral glass prism such that the refracted ray inside the prism is parallel to its base and emerges at an angle of emergence i2.
(i) How is the angle of emergence 'i2' related to the angle of incidence 'i1'.
(ii) What can you say about the angle of deviation in such a situation?