Mathematics

A guy attached a wire 24 m long to a vertical pole of height 18 m and has a stake attached to other end. How far from the base of the pole should the stake be driven so that the wire will be taught ?

Let BC be the pole and AB be the wire and let the distance of stake from base of pole be x.

Since, pole is vertical so △ABC is right triangle.

By pythagoras theorem,

⇒ AB² = BC² + AC²

⇒ 24² = 18² + x²

⇒ 576 = x² + 324

⇒ x² = 576 - 324 = 252

⇒ x = $\sqrt{252} = 6\sqrt{7}$ m.

Hence, the stake should be at a distance of $6\sqrt{7}$ m from the base of the pole.

Answered By