A conical pit of top diameter 3.5 m is 12 m deep. What is its capacity in kiloliters ?

Radius = $\dfrac{\text{Diameter}}{2} = \dfrac{3.5}{2} = 1.75$ m.

Height = 12 m.

Volume of cone = $\dfrac{1}{3}πr^2h$

Putting values in equation we get,

Volume of cone,

$= \dfrac{1}{3} \times \dfrac{22}{7} \times (1.75)^2 \times 12 = \dfrac{22 × 3.0625 × 12}{3 \times 7} = \dfrac{808.5}{21} = 38.5$ m³.

Since, 1 m³ = 1 kiloliters.

Hence, capacity of pit = 38.5 kiloliters.