A body of volume 100 cm 3 weighs 5 kgf in air. It is completely immersed in a liquid of density 1.8 x 10 3 kg m -3 . Find (i) the upthrust due to liquid and (ii) the weight of the body in liquid.

(i) As we know, Upthrust due to liquid = volume of the solid x density of fluid x acceleration due to gravity Given, Volume of the body = 100 cm 3 Converting cm 3 into m 3 100 cm = 1 m So, 100 cm x 100 cm x 100 cm = 1 m 3 Hence, 100 cm 3 = Therefore, V = 10 -4 m 3 Weight of the body in air = 5 kgf Density of the liquid = 1.8 x 10 3 kg m -3 Substituting the values in the formula above we get, Upthrust = 10 -4 x 1.8 x 10 3 x g = 0.18 kgf Hence, the upthrust due to liquid = 0.18 kgf (ii) weight of the body in liquid = weight of the body in air – upthrust Substituting the values in the formula above, we get, weight of the body in liquid = 5 kgf - 0.18 kgf = 4.82 kgf Hence, weight of the body in liquid = 4.82 kgf

Physics

A body of volume 100 cm³ weighs 5 kgf in air. It is completely immersed in a liquid of density 1.8 x 10³ kg m^-3. Find (i) the upthrust due to liquid and (ii) the weight of the body in liquid.

Fluids Upthrust

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Physics

A body of volume 100 cm³ weighs 5 kgf in air. It is completely immersed in a liquid of density 1.8 x 10³ kg m^-3. Find (i) the upthrust due to liquid and (ii) the weight of the body in liquid.

Fluids Upthrust

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A body of volume 100 cm3 weighs 5 kgf in air. It is completely immersed in a liquid of density 1.8 x 103 kg m-3. Find (i) the upthrust due to liquid and (ii) the weight of the body in liquid.

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Prove that the loss in weight of a body when immersed wholly or partially in a liquid is equal to the buoyant force (or upthrust) and this loss is because of the difference in pressure exerted by liquid on the upper and lower surfaces of the submerged part of the body.

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A body weighs 450 gf in air and 310 gf when completely immersed in water.Find —(i) the volume of the body,(ii) the loss in weight of the body, and(iii) the upthrust on the body.State the assumption made in part (i).

You are provided with a hollow iron ball A of volume 15 cm3 and mass 12 g and a solid iron ball B of mass 12 g. Both are placed on the surface of water contained in a large tub. (a) Find upthrust on each ball. (b) Which ball will sink ? Give reason for your answer. ( Density of iron = 8.0 g cm-3)

A body of volume 100 cm³ weighs 5 kgf in air. It is completely immersed in a liquid of density 1.8 x 10³ kg m^-3. Find (i) the upthrust due to liquid and (ii) the weight of the body in liquid.

A body weighs 450 gf in air and 310 gf when completely immersed in water.
Find —
(i) the volume of the body,
(ii) the loss in weight of the body, and
(iii) the upthrust on the body.
State the assumption made in part (i).

You are provided with a hollow iron ball A of volume 15 cm³ and mass 12 g and a solid iron ball B of mass 12 g. Both are placed on the surface of water contained in a large tub. (a) Find upthrust on each ball. (b) Which ball will sink ? Give reason for your answer. ( Density of iron = 8.0 g cm^-3)