Chemistry

800 cm³ of gas is collected at 654 mm pressure. At what pressure would the volume of the gas reduce by 40% of its original volume, temperature remaining constant?

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V₁ = 800 cm³

P₁ (Initial pressure) = 654 mm of Hg

V₂ = reduces by 40% of it's initial value

= 800 - ( $\dfrac{40}{100}$ x 800)

= 800 - 320 = 480 cm³

P₂ (Final pressure) = ?

By Boyle's Law:

$\text{P}$

Substituting the values :

$654 \times 800 = \text{P}$

∴ Final pressure of the gas = 1090 mm of Hg.

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