KnowledgeBoat Logo

Chemistry

At constant temperature, the effect of change of pressure on volume of a gas was as given below :

Pressure in atmospheresVolume in litres
1.012
1.58.0
2.06.0
2.54.8
3.04.0

(a) Plot the following graphs :

(i) P vs V

(ii) P vs 1/V

(iii) PV vs P

(b) Assuming that the pressure values given above are correct, find the correct measurement of the volume at 2.3 atmosphere pressure.

Gas Laws

90 Likes

Answer

(a)

(i) Graph of P vs V :

Pressure (atm)Volume (lit)
1.012.0
1.58.0
2.06.0
2.54.8
3.04.0
Graph of P vs V. Study of Gas Laws, Concise Chemistry Solutions ICSE Class 9.

(ii) Graph of P vs 1/V :

Pressure (atm)Volume (lit)1/V
1.0120.083
1.58.00.125
2.06.00.166
2.54.80.208
3.04.00.25
Graph of P vs 1/V. Study of Gas Laws, Concise Chemistry Solutions ICSE Class 9.

(iii) Graph of PV vs P :

Pressure (atm)Volume (lit)PV
1.01212
1.58.012
2.06.012
2.54.812
3.04.012
Graph of PV vs P. Study of Gas Laws, Concise Chemistry Solutions ICSE Class 9.

(b) By Boyle's Law:

P1V1=P2V2\text{P}1 \text{V}1 = \text{P}2 \text{V}2

P1V1 = 12 is a constant, hence, V2 = ? at P2 = 2.3 atm

Substituting the values :

12=2.3×V2V2=122.3V2=5.217 lit12 = 2.3 \times \text{V}2 \\[1em] \text{V}2 = \dfrac{12}{2.3} \\[1em] \text{V}_2 = 5.217 \text{ lit}

Hence, volume = 5.217 lit

Answered By

36 Likes


Related Questions