Chemistry
At constant temperature, the effect of change of pressure on volume of a gas was as given below :
Pressure in atmospheres | Volume in litres |
---|---|
1.0 | 12 |
1.5 | 8.0 |
2.0 | 6.0 |
2.5 | 4.8 |
3.0 | 4.0 |
(a) Plot the following graphs :
(i) P vs V
(ii) P vs 1/V
(iii) PV vs P
(b) Assuming that the pressure values given above are correct, find the correct measurement of the volume at 2.3 atmosphere pressure.
Gas Laws
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Answer
(a)
(i) Graph of P vs V :
Pressure (atm) | Volume (lit) |
---|---|
1.0 | 12.0 |
1.5 | 8.0 |
2.0 | 6.0 |
2.5 | 4.8 |
3.0 | 4.0 |

(ii) Graph of P vs 1/V :
Pressure (atm) | Volume (lit) | 1/V |
---|---|---|
1.0 | 12 | 0.083 |
1.5 | 8.0 | 0.125 |
2.0 | 6.0 | 0.166 |
2.5 | 4.8 | 0.208 |
3.0 | 4.0 | 0.25 |

(iii) Graph of PV vs P :
Pressure (atm) | Volume (lit) | PV |
---|---|---|
1.0 | 12 | 12 |
1.5 | 8.0 | 12 |
2.0 | 6.0 | 12 |
2.5 | 4.8 | 12 |
3.0 | 4.0 | 12 |

(b) By Boyle's Law:
P1V1 = 12 is a constant, hence, V2 = ? at P2 = 2.3 atm
Substituting the values :
Hence, volume = 5.217 lit
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