You have three resistors of values 2 Ω, 3 Ω and 5 Ω . How will you join them so that the total resistance is less than 1 Ω ? Draw diagram and find the total resistance.

In order to get a total resistance less than 1 Ω, the three resistors of values 2 Ω, 3 Ω and 5 Ω, should be connected in parallel as shown in the diagram below:

In parallel, if the equivalent resistance is R_P, then

$\dfrac{1}{R$P} = \dfrac{1}{R1} + \dfrac{1}{R2} + \dfrac{1}{R3} \\[0.5em] \dfrac{1}{RP} = \dfrac{1}{2} + \dfrac{1}{3} + \dfrac{1}{5} \\[0.5em] \dfrac{1}{RP} = \dfrac{15 + 10+ 6}{30} \\[0.5em] \dfrac{1}{RP} = \dfrac{31}{30} \\[0.5em] \Rightarrow RP = 0.97 Ω

Hence, the three resistors should be connected in parallel and total resistance = 0.97 Ω