(i) Define the term bandwidth with respect to networks.

(ii) How is http different from https ?

The code given below accepts a number as an argument and returns the reverse number. Observe the following code carefully and rewrite it after removing all syntax and logical errors. Underline all the corrections made.

define revNumber(num):
    rev = 0
    rem = 0
    While num > 0:
        rem == num % 10
        rev = rev * 10 + rem
        num = num//10
        return rev
print(revNumber(1234))

Write a function, lenWords(STRING), that takes a string as an argument and returns a tuple containing length of each word of a string. For example, if the string is "Come let us have some fun", the tuple will have (4, 3, 2, 4, 4, 3).

Predict the output of the following code:

S = "LOST"
L = [10, 21, 33, 4]
D = {}
for I in range(len(S)):
    if I % 2 == 0:
        D[L.pop()] = S[I]
    else:
        D[L.pop()] = I + 3
for K, V in D.items():
    print(K, V, sep = "*")