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Chemistry

Write a balanced chemical equation for -

(i) The formation of aluminium at the cathode, during the electrolysis of alumina

(ii) Action of heat on aluminium hydroxide.

Metallurgy

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Answer

(i) At cathode : 2Al3+ + 6e- ⟶ 2Al

(ii) Conversion of Al(OH)3 - to pure alumina - heat on Al(OH)3

2Al(OH)3[aluminium hydroxide]→1100°CAl2O3[pure alumina]+3H2O\underset{\text{[aluminium hydroxide]}}{\text{2Al(OH)}3} \xrightarrow{1100\degree\text{C}} \underset{\text{[pure alumina]}}{\text{Al}2\text{O}3} + \text{3H}2\text{O}

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