Mathematics
Without using set square or protractor, construct the quadrilateral ABCD in which ∠BAD = 45°, AD = AB = 6 cm, BC = 3.6 cm and CD = 5 cm.
(i) Measure ∠BCD.
(ii) Locate the point P on BD which is equidistant from BC and CD.
Locus
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Answer
Draw AB = 6 cm as base. Construct 90° from point A and bisect the angle and cut off AD = 6cm, such that ∠BAD = 45°.
From D cut an arc of 5 cm and from B cut an arc of 3.6 cm. C will be their point of intersection. Join the points forming quadrilateral ABCD.
(i) Measuring angle BCD from the figure we get,
∠BCD = 65°.
(ii) We know that locus of points equidistant from two lines is the angle bisector of angle between them.
From the figure,
CE is the angular bisector of ∠BCD, hence it will be equidistant from CD and BC.
CE meets BD at point P as marked in the figure.
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