Mathematics
Which of the following points lie on the graph of the equation :
3x - 5y + 7 = 0?
(1, -2)
(2, 1)
(-1, 2)
(1, 2)
Coordinate Geometry
6 Likes
Answer
Substituting (1, -2) in L.H.S. of the equation 3x - 5y + 7 = 0, we get :
⇒ 3x - 5y + 7
⇒ 3(1) - 5(-2) + 7
⇒ 3 + 10 + 7
⇒ 20
Since, L.H.S. ≠ R.H.S., (1, -2) does not satisfy the equation.
Substituting (2, 1) in L.H.S. of the equation 3x - 5y + 7 = 0, we get :
⇒ 3x - 5y + 7
⇒ 3(2) - 5(1) + 7
⇒ 6 - 5 + 7
⇒ 8
Since, L.H.S. ≠ R.H.S., (2, 1) does not satisfy the equation.
Substituting (-1, 2) in L.H.S. of the equation 3x - 5y + 7 = 0, we get :
⇒ 3x - 5y + 7
⇒ 3(-1) - 5(2) + 7
⇒ -3 - 10 + 7
⇒ -6
Since, L.H.S. ≠ R.H.S., (-1, 2) does not satisfy the equation.
Substituting (1, 2) in L.H.S. of the equation 3x - 5y + 7 = 0, we get :
⇒ 3x - 5y + 7
⇒ 3(1) - 5(2) + 7
⇒ 3 - 10 + 7
⇒ 0
Since, L.H.S. = R.H.S., (1, 2) satisfies the equation.
Hence, Option 4 is the correct option.
Answered By
2 Likes
Related Questions
If P(-1, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then point(s) in the fourth quadrant are
P and T
Q and R
S only
P and R
On plotting the points O(0, 0), A(3, 0), B(3, 4), C(0, 4) and joining OA, AB, BC, and CO which of the following figure is obtained?
Square
Rectangle
Trapezium
Rhombus
The pair of equation x = a and y = b graphically represents lines which are
parallel
intersecting at (b, a)
coincident
intersecting at (a, b)
The distance of the point P(2, 3) from the x-axis is
2 units
3 units
1 unit
5 units