Physics
When a screw gauge of least count 0.01 mm is used to measure the diameter of a wire, the reading on the sleeve is found to be 1 mm and the reading on the thimble is found to be 27 divisions.
What is the diameter of the wire in cm?
If the zero error is +0.005 cm, what is the correct diameter?
Measurements
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Answer
As we know,
Diameter of the wire = main scale reading + circular scale reading [Equation 1]
and
Reading on thimble = p x L.C. [Equation 2]
Given,
p = 27
L.C. = 0.01 mm = 0.001 cm
Substituting the values in the Equation 2 we get,
reading on thimble = 27 x 0.001 = 0.027 cm
Hence, reading on thimble = 0.027 cm and reading on sleeve = 1 mm = 0.1 cm
Using Equation 1 we get,
Diameter of the wire = 0.1 cm + 0.027 cm = 0.127 cm
Hence, the diameter of the wire is 0.127 cm.
(ii) As we know,
Correct reading = observed reading - zero error
Given,
Zero error = + 0.005 cm
Substituting the value of zero error in the formula above we get,
Correct reading = 0.127 cm - 0.005 cm = 0.122 cm
Hence, the correct diameter of the wire is 0.122 cm
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