Computer Applications
What will be the value of sum after each of the following nested loops is executed?
int sum = 0;
for (int i = 0; i <= 10; i++)
for (int j = 0; j <= 10; j++)
sum += i;
Java Nested for Loops
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Answer
Sum = 605
Explanation
The outer loop executes 11 times. For each iteration of outer loop, the inner loop executes 11 times. For every value of j, i is added to sum 11 times. Consider the following table for the value of sum with each value of i and j.
| i | j | Sum | Remarks |
|---|---|---|---|
| 0 | 0 - 10 | 0 | 0 is added to sum 11 times |
| 1 | 0 - 10 | 11 | 1 is added to sum 11 times ⇒ 0 + 11 = 11 |
| 2 | 0 - 10 | 33 | 2 is added to sum 11 times ⇒ 11 + 22 = 33 |
| 3 | 0 - 10 | 66 | 3 is added to sum 11 times ⇒ 33 + 33 = 66 |
| 4 | 0 - 10 | 110 | 4 is added to sum 11 times ⇒ 66 + 44 = 110 |
| 5 | 0 - 10 | 165 | 5 is added to sum 11 times ⇒ 110 + 55 = 165 |
| 6 | 0 - 10 | 231 | 6 is added to sum 11 times ⇒ 165 + 66 = 231 |
| 7 | 0 - 10 | 308 | 7 is added to sum 11 times ⇒ 231 + 77 = 308 |
| 8 | 0 - 10 | 396 | 8 is added to sum 11 times ⇒ 308 + 88 = 396 |
| 9 | 0 - 10 | 495 | 9 is added to sum 11 times ⇒ 396 + 99 = 495 |
| 10 | 0 - 10 | 605 | 10 is added to sum 11 times ⇒ 495 + 110 = 605 |
| 11 | Loop terminates |
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