Chemistry
What volume of oxygen is required to burn completely a mixture of 22.4 dm3 of methane and 11.2 dm3 of hydrogen into carbon dioxide and steam?
CH4 + 2O2 ⟶ CO2 + 2H2O
2H2 + O2 ⟶ 2H2O
Mole Concept
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Answer
From equation:
22.4 dm3 of methane requires oxygen = 2 x 22.4 dm3 of O2 = 44.8 dm3
From equation,
[2 x 22.4] dm3 hydrogen requires oxygen = 22.4 dm3
∴ 11.2 dm3 hydrogen will require oxygen = x 11.2 =
= 5.6 dm3
Total volume of oxygen required = 44.8 + 5.6 = 50.4 dm3
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