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Chemistry

What volume of ethyne gas at s.t.p. is required to produce 8.4 dm3 of carbon dioxide at s.t.p.?

2C2H2 + 5O2 ⟶ 4CO2 + 2H2O

[H = 1, C = 12, O = 16]

Stoichiometry

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Answer

[By Lussac's law]

2C2H2+5O2⟶4CO2+2H2O2 vol.:5 vol.⟶4 vol.:2 vol.\begin{matrix} 2\text{C}2\text{H}2 & + & 5\text{O}2 &\longrightarrow & 4\text{CO}2 & + & 2\text{H}_2\text{O} & \ 2 \text{ vol.} & : & 5 \text{ vol.} & \longrightarrow & 4\text{ vol.} & : & 2\text{ vol.} \end{matrix}

To calculate the volume of ethyne gas

CO2:C2H24:28.4:x\begin{matrix}\text{CO}2 & : & \text{C}2\text{H}_2 \ 4 & : & 2 \ 8.4 & : & x \end{matrix}

∴

24×8.4=4.2 dm3\dfrac{2}{4} \times 8.4 = 4.2 \text{ dm}^3

Hence, volume of ethyne gas required = 4.2 dm3.

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