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What number should be subtracted from 2x3 - 5x2 + 5x + 8 so that the resulting polynomial has a factor 2x - 3 ?

Factorisation

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Answer

Let no. to be subtracted be a.

So, resulting polynomial is 2x3 - 5x2 + 5x + 8 - a.

By factor theorem,

A polynomial f(x) has a factor (x - a), if and only if, f(a) = 0.

Given,

Factor : 2x - 3 = 0

x = 32\dfrac{3}{2}

Substituting value of x = 32\dfrac{3}{2} in 2x3 - 5x2 + 5x + 8 - a, will give remainder = 0.

2×(32)35×(32)2+5×32+8a=02×2785×94+152+8a=0274454+15+162a=0184+312a=018+624a=0444a=011a=0a=11.\Rightarrow 2 \times \Big(\dfrac{3}{2}\Big)^3 - 5 \times \Big(\dfrac{3}{2}\Big)^2 + 5 \times \dfrac{3}{2} + 8 - a = 0 \\[1em] \Rightarrow 2 \times \dfrac{27}{8} - 5 \times \dfrac{9}{4} + \dfrac{15}{2} + 8 - a = 0 \\[1em] \Rightarrow \dfrac{27}{4} - \dfrac{45}{4} + \dfrac{15 + 16}{2} - a = 0 \\[1em] \Rightarrow -\dfrac{18}{4} + \dfrac{31}{2} - a = 0 \\[1em] \Rightarrow \dfrac{-18 + 62}{4} - a = 0 \\[1em] \Rightarrow \dfrac{44}{4} - a = 0 \\[1em] \Rightarrow 11 - a = 0 \\[1em] \Rightarrow a = 11.

Hence, number to be subtracted is 11.

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