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Chemistry

What is the average atomic mass of bromine if it has 49.7% 7935Br and 50.3% 8135Br?

Atomic Structure

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Answer

Given,

49.7% of 7935Br and

50.3% of 8135Br

These isotopes are in the ratio = 49.750.3\dfrac{49.7}{50.3} = 497503\dfrac{497}{503}

Average atomic mass = (79×497)+(81×503)1000\dfrac{(79 \times 497)+(81 \times 503)}{1000}

=39263+(40743)1000=800061000=80.006 amu80 amu= \dfrac{39263+(40743)}{1000} \\[1em] = \dfrac{80006}{1000} \\[1em] = 80.006 \text{ amu} \\[1em] \approx 80 \text{ amu}

∴ Average atomic mass of bromine = 80 amu

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