Computer Science
What are the possible outcome(s) executed from the following code? Also specify the maximum and minimum values that can be assigned to variable NUMBER.
STRING = "CBSEONLINE"
NUMBER = random.randint(0, 3)
N = 9
while STRING[N] != 'L' :
print(STRING[N] + STRING[NUMBER] + '#', end = '')
NUMBER = NUMBER + 1
N = N - 1
- ES#NE#IO#
- LE#NO#ON#
- NS#IE#LO#
- EC#NB#IS#
Python Libraries
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Answer
The outcomes are as follows:
ES#NE#IO#
EC#NB#IS#
NUMBER is assigned a random integer between 0 and 3 using random.randint(0, 3). Therefore, the minimum value for NUMBER is 0 and the maximum value is 3.
Explanation
Length of STRING having value "CBSEONLINE" is 10. So the character at index 9 is "E". Since the value of N starts at 9 the first letter of output will be "E". This rules out LE#NO#ON# and NS#IE#LO# as possible outcomes as they don't start with "E". NUMBER is a random integer between 0 and 3. So, the second letter of output can be any letter from "CBSE". After that, NUMBER is incremented by 1 and N is decremented by 1.
In next iteration, STRING[N] will be STRING[8] i.e., "N" and STRING[NUMBER] will be the letter coming immediately after the second letter of the output in the string "CBSEONLINE" i.e., if second letter of output is "S" then it will be "E" and if second letter is "C" then it will be "B".
In the third iteration, STRING[N] will be STRING[7] i.e., "I" and STRING[NUMBER] will be the letter coming immediately after the fourth letter of the output in the string "CBSEONLINE" i.e., if fourth letter of output is "E" then it will be "O" and if fourth letter is "B" then it will be "S".
After this the while loop ends as STRING[N] i.e., STRING[6] becomes "L". Thus both, ES#NE#IO# and EC#NB#IS# can be the possible outcomes of this code.
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