Computer Applications
Two strings, city1 and city2, are compared using city1.compareTo(city2), and the result is less than zero. What does this indicate?
Java String Handling
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Answer
city1 appears before city2 in an alphabetical list.
Reason — The method compareTo(String s) in Java compares two strings lexicographically. It returns:
- A negative value if the calling string (
city1) comes before the argument string (city2) in alphabetical order. - 0 if the two strings are equal.
- A positive value if the calling string (
city1) comes after the argument string (city2) in alphabetical order.
If the result is less than zero, it indicates that city1 appears before city2 lexicographically (alphabetically).
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