Physics
Two forces each of magnitude 10N act vertically upwards and downwards respectively at the two ends A and B of a uniform rod of length 4m which is pivoted at its mid-point O as shown. Determine the magnitude of resultant moment of forces about the pivot O.
Force
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Answer
Given,
Ab = 4m
OA = 2m
OB = 2m
Force at A = 10N
Force at B = 10N
As we know ,
Moment of force = F x r
Substituting the values of F and r
Moment of force about o at point A
Moment of force about o at point B
Total moment of forces about the centre O
Total moment of force about the pivot O is 40 Nm (clockwise)
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