Physics

Two balls of masses 4m and 8m are in motion with velocities 2v and v respectively. The ratio of their momentum would be :
2 : 1
1 : 2
1 : 1
1 : 4

Laws of Motion

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Answer

1 : 1

Reason — Given,

m₁ = 4m m₂ = 8m
v₁ = 2v
v₂ = v

As, p = mv

Hence, $\dfrac{\text{p}$ = $\dfrac{\text{4\text{m}2\text{v}}}{\text{8\text{m}\text{v}}}$ = $\dfrac{\text{8\text{mv}}}{\text{8\text{m}\text{v}}}$ = 1 : 1

Hence, ratio of their momentum = 1 : 1

Answered By

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Physics

Two balls of masses 4m and 8m are in motion with velocities 2v and v respectively. The ratio of their momentum would be :
2 : 1
1 : 2
1 : 1
1 : 4

Laws of Motion

Answer

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2 : 1
1 : 2
1 : 1
1 : 4

For a relation F = $\dfrac{m(Δv)}{Δt}$ , to hold true, the condition(s) necessary is/are:
velocities are equal to the velocity of light
velocities are much smaller than the velocity of light
mass remains constant
both (b) and (c)

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2.5 N
20 N
10 N
25 N

1 Newton is equal to :
10³ dyne
10⁸ dyne
10¹⁰ dyne
10⁵ dyne

According to Newton's second law of motion, the change in momentum takes place in a direction :
opposite to the direction of force applied
perpendicular to the direction of the force applied
similar to the direction of the force applied
none of these