KnowledgeBoat Logo

Mathematics

Three coins are tossed simultaneously the probability of getting atleast two heads is :

  1. 12\dfrac{1}{2}

  2. 13\dfrac{1}{3}

  3. 14\dfrac{1}{4}

  4. 38\dfrac{3}{8}

Probability

1 Like

Answer

When three coins are tossed together; the possible outcomes are :

HHH, HHT, HTH, THH, HTT, THT, TTH and TTT.

i.e., the total number of possible outcomes = 8

Favorable outcomes for getting atleast two heads are : HHH, HHT, HTH, THH.

i.e., the number of favorable outcomes = 4

P(getting atleast two heads) : No. of favourable outcomesTotal no. of possible outcomes=48=12\dfrac{\text{No. of favourable outcomes}}{\text{Total no. of possible outcomes}} = \dfrac{4}{8} = \dfrac{1}{2}.

Hence, Option 1 is the correct option.

Answered By

1 Like

Related Questions