The width of each of 5 continuous classes in a frequency distribution is 5 and the lower limit of the lowest class is 10. The upper limit of the highest class is

1. 15

2. 25

3. 35

4. 40

Let x and y be the upper and lower class limit of frequency distribution.

Given,

Width of class = 5

∴ x - y = 5

⇒ x - 10 = 5

⇒ x = 5 + 10 = 15.

Upper class limit of highest class = No. of continuous class × Width + Lower class limit of lowest class

= 5 × 5 + 10

= 25 + 10

= 35.

Hence, Option 3 is the correct option.