Mathematics
The water bills (in rupees) of 32 houses in a locality are given below:
30, 48, 52, 78, 103, 85, 37, 94, 72, 73, 66, 52, 92, 65, 78, 81, 64, 60, 75, 78, 108, 63, 71, 54, 59, 75, 100, 103, 35, 89, 95, 73.
Taking class intervals 30 - 40, 40 - 50, 50 - 60, ……, form frequency distribution table.
Construct a combined histogram and frequency polygon.
Statistics
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Answer
First represent the given data in the form of a frequency distribution table.
Here, class intervals represent water bills class and frequency represents no. of houses.
Class Intervals | Class marks | Tally Marks | Frequency |
---|---|---|---|
30 - 40 | 35 | III | 3 |
40 - 50 | 45 | I | 1 |
50 - 60 | 55 | IIII | 4 |
60 - 70 | 65 | 5 | |
70 - 80 | 75 | 9 | |
80 - 90 | 85 | III | 3 |
90 - 100 | 95 | III | 3 |
100 - 110 | 105 | IIII | 4 |
Steps of construction of histogram :
Take 1 cm along x-axis = 10 units.
Take 1 cm along y-axis = 1 unit.
Construct rectangles corresponding to the above continuous frequency distribution table.
The required histogram is shown in the adjoining figure.
Steps of construction of frequency polygon :
Mark the mid-points of upper bases of rectangles of the histogram.
Join the consecutive mid-points by line segments.
Join the first end point with the mid-point of class 20 - 30 with zero frequency, and join the other end point with the mid-point of class 110 - 120 with zero frequency.
The required frequency polygon is shown by thick line segments in the diagram.
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